2r^2-(2/3)r=0

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Solution for 2r^2-(2/3)r=0 equation: 


r in (-oo:+oo)

2*r^2-((2/3)*r) = 0

2*r^2+(-2/3)*r = 0

2*r^2-2/3*r = 0

DELTA = (-2/3)^2-(0*2*4)

DELTA = 4/9

DELTA > 0

r = ((4/9)^(1/2)+2/3)/(2*2) or r = (2/3-(4/9)^(1/2))/(2*2)

r = 1/3 or r = 0

r in { 0, 1/3 }

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